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Word problems on simple equations

takriban dakika 1 kusoma

Mada za sehemu hiiAlgebraMada 5

Example 1

Ali bought a bus ticket for 450 shillings to travel to school and remained with 1,750 shillings. How much money did he have?

Solution

Let yy be the total amount of money Ali had before buying a ticket.

Therefore, the equation will be: y450=1750y - 450 = 1750

Add 450 on both sides of the equation.

y450+450=1750+450y - 450 + 450 = 1750 + 450

y+0=2200y + 0 = 2200

y=2200y = 2200

Therefore, Ali had 2,200 shillings.

Example 2

Rehema is 5 years older than Kemi. If the sum of their ages is 25 years, find their ages.

Solution

Form a simple equation by choosing any variable.

Let xx be the age of Kemi.

Note that Rehema is 5 years older than Kemi. Thus, add 5 to Kemi's age to get Rehema's age.

That is, Rehema's age = x+5x + 5

So the simple equation is, (x+5)+x=25(x + 5) + x = 25.

Collect the terms with variable and add them.

x+x+5=25x + x + 5 = 25

2x+5=252x + 5 = 25

Subtract 5 from both sides of the equation.

2x+55=2552x + 5 - 5 = 25 - 5

2x+0=202x + 0 = 20

2x=202x = 20

Divide both sides by 2 to get the value of xx.

2x2=202\frac{2x}{2} = \frac{20}{2}

x=10x = 10

Therefore, Kemi's age is 10 years.

Rehema's age = 10+5=1510 + 5 = 15 years.

Example 3

The age of Furaha is 12\frac{1}{2} of the age of her aunt. If the sum of their ages is 54 years, find their ages.

Solution

Let xx be the age of Furaha's aunt.

The age of Furaha = 12x\frac{1}{2}x

But the sum of their ages is 54 years.

Thus, the simple equation is given by:

x+12x=54x + \frac{1}{2}x = 54

2x+x2=54\frac{2x + x}{2} = 54

3x2=54\frac{3x}{2} = 54

Multiply both sides of the equation by 2 to get:

3x2×2=54×2\frac{3x}{2} \times 2 = 54 \times 2

3x=1083x = 108

Divide by 3 on both sides

3x3=1083\frac{3x}{3} = \frac{108}{3}

x=36x = 36

Thus, the age of Furaha's aunt is 36 years. The age of Furaha is given by:

12x=12×36=18\frac{1}{2}x = \frac{1}{2} \times 36 = 18

Therefore, the age of Furaha is 18 years.

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