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Chemistry 1

The Quantum Theory

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States that: “Matter has particle nature as well as wave nature”.  Wave-particle duality refers to the concept that matter and radiation can exhibit both wave-like and particle-like properties. This theory was proposed by Louis de Broglie. He suggested that all matter has both wave and particle properties, and he derived an expression to calculate the wavelength of matter (called the de Broglie wavelength). The de Broglie wavelength λ of a particle can be expressed in terms of its momentum p as:

λ = h / p

Where:

h is Planck's constant (6.63 x 10^-34^ J·s)

p is the momentum of the particle (p = mv, where m is the mass and v is the velocity of the particle)

De Broglie's wavelength in terms of energy:

From Einstein's equation, we know that the energy of a particle at rest is given by:

E = mc2 (1)

From Planck's equation for energy of a photon:

E = hc / λ (2)

Now, compare equations (1) and (2):

mc2 = hc / λ

Solving for the de Broglie wavelength:

\lambda = \frac{h}{mv} $$Where | | | | --- | --- | | $\lambda$ | = wavelength in meters | | v | = the velocity in meters/sec | | m | = the mass in kilograms | | h | = Planck's constant in J/Hz | ### Examples: 1. Alpha particles emitted from radium have energy of 4.4 MeV. What is the de Broglie wavelength? Given: E = 4.4 MeV = 4.4 × 10^6^ eV Using equation (3), convert energy to joules and solve for wavelength. 2. The mass of a moving particle is 9.01 × 10^-19^ g. What is the de Broglie wavelength? Given: m = 9.01 × 10^-19^ g = 9.01 × 10^-22^ kg Using equation (3), calculate the wavelength. 3. The momentum of particles is 2.0 × 10^-10^ g·m/s. What is the de Broglie wavelength? Given: p = 2.0 × 10^-10^ g·m/s = 2.0 × 10^-13^ kg·m/s Use the formula λ = h / p to find the wavelength.

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