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Basic Applied Mathematics 2

Graphs of linear inequalities

takriban dakika 3 kusoma

Mada za sehemu hiiLinear ProgrammingMada 5

Graphs of linear inequalities

The graph of a linear inequality in two variables represents all points in the xy-plane that satisfy the inequality. The boundary of this region is a straight line.

Linear inequalities discussed here have the forms:

  1. ax+bycax + by \le c
  2. ax+bycax + by \ge c
  3. ax+by<cax + by < c
  4. ax+by>cax + by > c

where aa, bb, and cc are real numbers, and (a,b)(0,0)(a, b) \neq (0,0).

Steps for graphing linear inequalities

  1. Replace the inequality with an equality: Change the inequality symbol to an equal sign to get the equation of the boundary line.
  2. Draw the boundary line:
    • Use a dotted line for strict inequalities (< or >).
    • Use a solid line for inclusive inequalities (≤ or ≥).
  3. Choose a test point: Select a convenient point not on the boundary line. The origin (0,0) is often a good choice.
  4. Test the inequality: Substitute the coordinates of the test point into the original inequality.
    • If the inequality is true, shade the region containing the test point.
    • If the inequality is false, shade the region opposite the test point.

Examples

Example 11.3: Graph 2x+y42x + y \le 4

Solution:

  1. Boundary line: 2x+y=42x + y = 4

  2. Draw the line: Since the inequality is ≤, use a solid line. Find the intercepts:

    xy
    04
    20
  3. Test point: Choose (0,0).

  4. Test the inequality: 2(0)+04042(0) + 0 \le 4 \Rightarrow 0 \le 4 (True)

Since the inequality is true for (0,0), shade the region containing the origin (see below).

Graph of 2x + y ≤ 4

Example 11.4: Graph 3x+2y63x + 2y \ge 6

Solution:

  1. Boundary line: 3x+2y=63x + 2y = 6

  2. Draw the line: Use a solid line (≥). Find the intercepts:

    xy
    03
    20
  3. Test point: Choose (0,0).

  4. Test the inequality: 3(0)+2(0)6063(0) + 2(0) \ge 6 \Rightarrow 0 \ge 6 (False)

Since the inequality is false for (0,0), shade the region opposite the origin (see below).

Graph of 3x + 2y ≥ 6

Example 11.5: Graph the system

{2x+y102x+3y18x0y0\begin{cases} 2x + y \le 10 \\ 2x + 3y \le 18 \\ x \ge 0 \\ y \ge 0 \end{cases}

Solution:

  1. Boundary lines: 2x+y=102x + y = 10, 2x+3y=182x + 3y = 18, x=0x = 0, y=0y = 0

  2. Draw the lines: Use solid lines (≤, ≥). Find intercepts:

    Equationx-intercepty-intercept
    2x + y = 10510
    2x + 3y = 1896
  3. Test point: Choose (0,0).

  4. Test the inequalities:

    • 2(0)+0100102(0) + 0 \le 10 \Rightarrow 0 \le 10 (True)
    • 2(0)+3(0)180182(0) + 3(0) \le 18 \Rightarrow 0 \le 18 (True)
    • 000 \ge 0 (True)
    • 000 \ge 0 (True)

Shade the region where all inequalities are true. This will be the region bounded by the lines in the first quadrant (because of x0x \ge 0 and y0y \ge 0).

Graph of system of linear inequalities

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