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Find the general term for AP and GP and use them to derive formulae for the sums of APs and GPs

takriban dakika 4 kusoma

Mada za sehemu hiiUse sets, sequences and series in problem solvingMada 3

An arithmetic progression is a sequence of numbers where each term increases or decreases by a constant amount called the common difference (d). The first term is denoted by a.

General Term of an AP

The general (nth) term of an AP is given by:

an=a+(n1)da_n = a + (n - 1)d

This formula works because:

  • First term: a₁ = a + (1 - 1)d = a
  • Second term: a₂ = a + (2 - 1)d = a + d
  • Third term: a₃ = a + (3 - 1)d = a + 2d
  • And so on...

Deriving the Sum Formula for an AP

To find the sum of the first n terms (Sₙ), write the series forwards and backwards, then add them:

Sn=a+(a+d)+(a+2d)+...+[a+(n1)d]S_n = a + (a + d) + (a + 2d) + ... + [a + (n-1)d]

Write it in reverse:

Sn=[a+(n1)d]+[a+(n2)d]+...+aS_n = [a + (n-1)d] + [a + (n-2)d] + ... + a

Adding both expressions term by term:

2Sn=[a+a+(n1)d]+[a+d+a+(n2)d]+...+[a+(n1)d+a]2S_n = [a + a + (n-1)d] + [a + d + a + (n-2)d] + ... + [a + (n-1)d + a]

Each pair sums to: 2a + (n - 1)d

There are n such pairs, therefore:

2Sn=n[2a+(n1)d]2S_n = n[2a + (n - 1)d]

Sn=n2[2a+(n1)d]S_n = \frac{n}{2}[2a + (n - 1)d]

This is the sum formula for an Arithmetic Progression.

Worked Example

Find the sum of the first 20 terms of the AP: 5, 8, 11, 14, ...

Solution:

Given: first term a = 5, common difference d = 8 - 5 = 3, number of terms n = 20

Using the sum formula:

S20=202[2(5)+(201)(3)]S_{20} = \frac{20}{2}[2(5) + (20 - 1)(3)]

S20=10[10+19×3]S_{20} = 10[10 + 19 \times 3]

S20=10[10+57]S_{20} = 10[10 + 57]

S20=10×67=670S_{20} = 10 \times 67 = 670

Therefore, the sum of the first 20 terms is 670.


Swali

What is the 10th term of the arithmetic progression 5,8,11,14,5, 8, 11, 14, \dots?

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