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Solve quadratic equations by using different methods (factorisation, completing the square, and quadratic formula)

takriban dakika 6 kusoma

Mada za sehemu hiiUse algebra and matrices in problem solvingMada 6

A quadratic equation is an equation of the form ax2+bx+c=0ax^2 + bx + c = 0, where aa, bb, and cc are numbers and a0a \neq 0. The solutions of a quadratic equation are also called roots or zeros. In this topic, you will learn three methods for finding these solutions: factorization, completing the square, and the quadratic formula.

Factorization is the simplest method when the quadratic expression can be written as a product of two linear factors. This method uses the Zero Factor Theorem: if the product of two factors equals zero, then at least one of the factors must be zero.

Steps for Factorization

  1. Write the equation in standard form: ax2+bx+c=0ax^2 + bx + c = 0
  2. Factorize the quadratic expression into two linear factors
  3. Set each factor equal to zero
  4. Solve each simple equation to find the roots

Worked Example

Solve the equation x2+5x+6=0x^2 + 5x + 6 = 0

Solution

The quadratic expression is x2+5x+6x^2 + 5x + 6. We need to find two numbers that multiply to give 6 and add to give 5.

The numbers are 2 and 3, because 2×3=62 \times 3 = 6 and 2+3=52 + 3 = 5.

So, x2+5x+6=(x+2)(x+3)=0x^2 + 5x + 6 = (x + 2)(x + 3) = 0

Now apply the Zero Factor Theorem:

  • x+2=0x + 2 = 0 or x+3=0x + 3 = 0
  • Therefore, x=2x = -2 or x=3x = -3

Another Example

Solve 2x2+7x+3=02x^2 + 7x + 3 = 0

Solution

Here a=2a = 2, b=7b = 7, c=3c = 3, so ac=2×3=6ac = 2 \times 3 = 6.

Find two numbers whose product is 6 and whose sum is 7: these numbers are 6 and 1.

Split the middle term: 2x2+6x+x+3=02x^2 + 6x + x + 3 = 0 =2x(x+3)+1(x+3)=0= 2x(x + 3) + 1(x + 3) = 0 =(x+3)(2x+1)=0= (x + 3)(2x + 1) = 0

Thus, x+3=0x + 3 = 0 or 2x+1=02x + 1 = 0 x=3x = -3 or x=12x = -\frac{1}{2}

Swali

What are the roots of the quadratic equation x25x+6=0x^2 - 5x + 6 = 0 when solved by factorisation?

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